Question

Log x na base 256 = 1/4, me ajudem pfv..

Answer 1

log₂x + log₄y = 4 

log₂x + log₂y / log₂4 = 4 

log₂x + log₂y / 2 = 4............(*2) mmc 

2.log₂x + log₂y = 8 

log₂x² + log₂y = 8 

log₂[x².y] = 8 

x².y = 2⁸ 

x.(x.y) = 256 

x.(8) = 256 

x= 256/8 = 32 >> 


x.y = 8 
32.y=8 
y = 8/32 = 1/4 >