Question

X+y+z=0
2x-3y+5z=0
4x+7y-3z=0

Answer 1

Vou resolver pela regra de cramer.

x+y+z=0
2x-3y+5z=0
4x+7y-3z=0

|1 1 1 1 1 |
|2 -3 5 2 -3|
|4 7 -3 4 7 |
D=9+20+14+6-35
D=26

|0 1 1 0 1 |
|0 -3 5 0 -3|
|0 7 -3 0 7 |
DX=0
x= 0/26
x=0

|1 0 1 1 0 |
|2 0 1 2 0 |
|4 0 -3 4 0|
Dy= 0
y=0/26
y=0

|1 1 0 1 1 |
|2 -3 0 2 -3|
|4 7 0 4 7 |
Dz=0
z= 0/26
z=0