Question

(2x+1)² - 5(2x+1)+4=0 formula de baskara

Answer 1

(2x + 1)² - 5 (2x + 1) + 4 = 0
(2x)² + 2 . 2x . 1 + 1² - 10x - 5 + 4 = 0
4x² + 4x + 1 - 10x - 1 = 0
4x² + 4x - 10x + 1 - 1 = 0
4x² - 6x = 0
a = 4, b = - 6, c = 0

Δ = b² - 4ac
Δ = (- 6)² - 4 . 4 . 0
Δ = 36

x = (- b ± √Δ)/2a
x = (- (- 6) ± √36)/(2 . 4)
x = (6 ± 6)/8

x' = (6 + 6)/8 = 12/8 = 3/2
x'' = (6 - 6)/8 = 0/8 = 0

x' = 3/2, x'' = 0

Answer 2

(2x+1)² - 5(2x+1) + 4 = 0
4x²+4x+1-10x-5+4 = 0
4x²-6x = 0

Δ = b²-4ac
Δ = (-6)²-4(4)(0)
Δ = 36

x = -b+-√Δ / 2a
x = 6+-6 / 2(4)

x' = 6+6 / 8 = 12/8 = 3/2

x'' = 6-6 8 = 0/8 = 0