Question

me ajudem por favor

Answer 1

A)
$\frac{x}{6}$ + \[tex] \frac{x}{3} [/tex  - 18 = [tex] \frac{x}{4} [/tex

Mmc{3,4 e 6)=12

 [tex] \frac{2x + 4x - 216 }{12} ]  =[tex] \frac{3x}{12} 

2x+4x-216=3x

6x - 216 = 3x
3x= 216
x = [tex] \frac{216}{3}
x=72

B)  \frac{x}{4} +  \frac{x}{6} +  \frac{x}{8} = 26
Mmc{4,6 e 8} = 24

\frac{6x + 4x + 3x}{24}  =  24· 26
13x=624
x=48

C)  \frac{x}{8} +  \frac{x}{5}  = 17 -  \frac{x}{10} 

Mmc{5,8 e 10}= 40

 \frac{5x+8x}{40}  =  \frac{680-4x}{40} 
13x=680 - 4x
13x + 4x=680
17x=680
x=  \frac{680}{17}
x= 40


D)  \frac{x}{4} -  \frac{x}{3} = 2X - 50 
Mmc{3 e 4}= 12

 \frac{3x - 4x}{12} =   \frac{24X}{12}
- x - 24x= - 600        
-25x = - 600        (Multiplicando ambos por -1)
25x=600
x=  \frac{600}{25}
x= 24


Espero ter ajudado...

Answer 2

x+x+x=26
4 6 8

24×x+24×x+24×x=24×26
4 6 8

6x+4x+3x=624

13x=624

x=48


x+x=17-x
8 5 10

40×x+40×x=40×17-40×x
10
5x+4x+=680-4x

9x=680-4x

9x+4x=680

13x=680

x=680
13
8 10