Question

Usando o método que achar mais conveniente , determine a solução dos sistemas de equação. {x-2y=-16
{8x+3y=64

Answer 1

Olá.

$\mathsf{ \left \{ {{x-2y=-16} \atop {8x+3y=64}} \right.} \\\\\\\mathsf{x=-16+2y}\\\mathsf{8\cdot(-16+2y)+3y=64}\\\mathsf{-128+16y+3y=64}\\\mathsf{19y=128+64}\\\mathsf{19y=192}\\\boxed{\mathsf{y=\dfrac{192}{19}}}\\\\\\\\\mathsf{x-2y=-16}\\\mathsf{x-2\cdot(\dfrac{192}{19})=-16}\\\\\mathsf{x-\dfrac{384}{19}=-16}\\\\\mathsf{\dfrac{19x-384}{19}=-16}\\\\\mathsf{19x-384=-16\cdot19}\\\mathsf{19x=384-304}\\\mathsf{19x=80}\\\\\boxed{\mathsf{x=\dfrac{80}{19}}}$

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Bons estudos.