Question

Sabendo que log a= 2 , log b= 3 e log c= -6, o valor de log ⁵√a²b²/c³ é igual a:
a)16/5
b)28/5
c)32/5
d)1
e)2

Answer 1

n = 5

log ⁿ√(a²b²)/c³
log ⁿ√a²b² - log c³
log ⁿ√a²b² - 3log c
log a^2/n b^2/n -3log c
log a^2/n + log b^2/n -3log c
(2/n log a) + (2/n log b) - (3log c)
(2/n*2) + (2/n*3) - (3*-6)
4/n + 6/n +18
(4+6+18n)/n
(10+18.5)/5
20

Bons estudos :)