Question

equações literais: x2-cx-6c2=0
qual é o resultado ?

Answer 1

$x^2-cx-6c^2=0$

$\Delta=(-c)^2-4\cdot1\cdot(-6c^2)=c^2+24c^2=25c^2$

$x=\dfrac{-(-c)\pm\sqrt{25c^2}}{2\cdot1}=\dfrac{c\pm5c}{2}$.

$x'=\dfrac{c+5c}{2}=3c$

$x"=\dfrac{c-5c}{2}=-2c$.

$S=\{-2c, 3c\}$

Answer 2

x^2-cx-6c^2

a=1
b=-c
c=-6c^2

Achando delta
delta=b^2-4ac
delta= (-c)^2-4.1.(-6c^2)
delta=c^2+24c^2
delta=c^2.(1+24)
delta=25c^2

aplicando baskara:
x=[-b+-raiz(delta)]/2a

x=[-(-c)+-raiz(25c^2)]/2.1
x=( c+-5c)/2
x'=(c+5c)/2=6c/2=3c
x"=(c-5c)/2=-4c/2=-2c

raízes para a equação s={-2c; 3c}