Question

Como resolver eta equacão:
3X ao quadrado -x-2=0

Answer 1

$3x^2-x-2=0$

$\Delta=(-1)^2-4\cdot3\cdot(-2)=1+24=25$

$x=\dfrac{-(-1)\pm\sqrt{25}}{2\cdot3}=\dfrac{1\pm5}{6}$

$\boxed{x'=\dfrac{1+5}{6}=1}$

$\boxed{x"=\dfrac{1-5}{6}=\dfrac{-2}{3}}$

Answer 2

3x² -x -2=0
Δ= b²-4ac
Δ= (-1)² - 4.3. (-2)
Δ= 1 + 24
Δ=25

x= -b +/- √Δ / 2a
x= -(-1) +/- √25 / 2.3
x'= 1 +5 /6
x'= 6/6
x'=1

x''= 1-5 /6
x''= -4/6