Question

Quanto dá a conta: {5+[4^3÷(3^2-1)+1^5×3]}÷(6-2)^2

Answer 1

 {5+[4^3÷(3^2-1)+1^5×3]}÷(6-2)^2

 {5+[64÷(9-1)+1×3]}÷(4)^2

 {5+[64÷8+3]}÷16 ==>  {5+[8+3]}÷16

 {5+11]}÷16 ==> 16÷16 ==> 1