Question

Seja f(x) =  x² +4x – 6, determine o valor de f(x+1)

Answer 1

f(x) = x² + 4x - 6   ; f(x + 1)
f( x + 1) = (x + 1)² + 4(x + 1) - 6
f(x + 1) = x² + 2x + 1 +4x + 4 - 6
f(x + 1) = x² + 6x - 1

Answer 2

x² + 4x - 6
( x + 1 ) ² + 4 ( x + 1 ) - 6
( x + 1 ) . ( x + 1 ) + 4x + 4 - 6
x² + x + x + 1 + 4x + 4 - 6
x² + 6x - 1

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