• Matéria: Matemática
  • Autor: Sammantha
  • Perguntado 8 anos atrás

{[(7,444...) elevado ao quadrado +1,666]×(0,999÷3,6222)}

Anexos:

TesrX: Se ninguém responder até 00:00, respondo. :)
Sammantha: obgd
TesrX: Tô na faculdade, é difícil de digitar. :x
Sammantha: tudo bem!
Sammantha: como é a resposta final?!

Respostas

respondido por: TesrX
1
Olá.

\mathsf{\{[(7,\overline{444}...)^2+1,\overline{666}]\cdot(0,\overline{999}/3,6\overline{222})\}}=\\\\\mathsf{\left\{\left[\left(7+0,\overline{444}\right)^2+\left(1+0,\overline{666}\right)\right]\cdot\left(\dfrac{9}{9}/\left(3+0,6\oveline{222}\right)\right)\right\}}=\\\\\\\mathsf{\left\{\left[\left(7+\dfrac{4}{9}\right)^2+\left(1+\dfrac{6}{9}\right)\right]\cdot\left(\dfrac{9}{9}/\left(3+\dfrac{62-6}{90}\right)\right)\right\}}=

\mathsf{\left\{\left[\left(\dfrac{7\cdot9+4}{9}\right)^2+\left(\dfrac{1\cdot9+6}{9}\right)\right]\cdot\left(\dfrac{9}{9}/\left(3+\dfrac{58}{90}\right)\right)\right\}}=\\\\\\\mathsf{\left\{\left[\left(\dfrac{63+4}{9}\right)^2+\left(\dfrac{9+6}{9}\right)\right]\cdot\left(\dfrac{9}{9}/\left(\dfrac{3\cdot90+58}{90}\right)\right)\right\}}=\\\\\\\mathsf{\left\{\left[\left(\dfrac{67}{9}\right)^2+\left(\dfrac{15}{9}\right)\right]\cdot\left(\dfrac{9}{9}/\dfrac{270}{90}\right)\right\}}=

\mathsf{\left\{\left[\dfrac{4.489}{81}+\dfrac{15}{9}\right]\cdot\left(\dfrac{9}{9}\cdot\dfrac{90}{270}\right)\right\}}=\\\\\\\mathsf{\left\{\left[\dfrac{4.489+15\cdot9}{81}\right]\cdot\left(\dfrac{810}{2.430}\right)\right\}}=\\\\\\\mathsf{\left\{\left[\dfrac{4.489+135}{81}\right]\cdot\left(\dfrac{810}{2.430}\right)\right\}}=\\\\\\\mathsf{\left\{\left[\dfrac{4.624}{81}\right]\cdot\left(\dfrac{810}{2.430}\right)\right\}}=

\mathsf{\dfrac{4.624\cdot810}{81\cdot2.430}=\boxed{\mathsf{\left(\dfrac{3.760.020}{196.830}\right)^{:810}=\boxed{\mathsf{\dfrac{4.642}{243}}}}}}


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Bons estudos.
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