Question

Calcule as medidas de x, y e z no esquema a seguir.

Answer 1

$\frac{z}{100}= \frac{z+y}{230}= \frac{x+y+z}{380} = \frac{304}{380}= \frac{76}{95}= \frac{4}{5} \\ \\ \frac{z}{100}= \frac{4}5} \\ \\ 5z=400 \\ \\ z= \frac{400}{5} \\ \\ z=80 \\ \\ \frac{80+y}{230}= \frac{4}{5} \\ \\ 5(80+y)=4*230 \\ \\ 80+y=4*46 \\ \\ y=184-80 \\ \\ y=104 \\ \\ \frac{x+80+104}{380}= \frac{4}{5} \\ \\ 5(x+184)=4*380 \\ \\ x+184=4*76 \\ \\ x=304-184 \\ \\ x=120 \\ \\ Resp. \\ \\ x=120 \\ y=104 \\ z=80$