Question

$x^{2} - 5x + 6 \ \textgreater \ 0$

Answer 1

Olá.

$\mathff{x^2-5x+5\ \textgreater \ 0}\\\\ \mathsf{\Delta=b^2-4ac=(-5)^2-4\cdot1\cdot6=25-24=\boxed{\mathsf{1}}}\\\\\\ \mathsf{x=\dfrac{-b\pm\sqrt\Delta}{2a}=\dfrac{-(-5)\pm1}{2\cdot1}=\dfrac{5\pm1}{2}}\\\\\\\mathsf{x'=\dfrac{5+1}{2}=\dfrac{6}{2}=3}\\\\\mathsf{x''=\dfrac{5-1}{2}=\dfrac{4}{2}=2}\\\\\\\mathsf{S=\{2,\ 3\}}$

Todo modo, x>0

Qualquer dúvida, deixe nos comentários.
Bons estudos.