Question

Dado o log2=a e log3=b calcule log 20

Answer 1

$log 2 = a \\ \\ log 3 = b \\ \\ log 20 = log 4.5 = log 4 + log 5 = log 2^{2} + log 5 \\ \\ 2.log 2 + log \frac{10}{2} = 2.log 2 + log 10 - log 2 \\ \\ 2.a + 1 - a \\ \\ log 20 = a + 1$

Espero ter ajudado.