Question

Resolva a inequação. $49^2^-^x \leq 1/7$

Answer 1

$49^{2-x} \leq \frac{1}{7}$
$7^{2(2-x)} \leq \frac{1}{7}$
$7^{4-2x} \leq 7^{-1}$
$4-2x \leq -1$
$-2x \leq -1-4$
$-2x \leq -5$ .(-1)
$2x \geq 5$
$x \geq \frac{5}{2}$