Question

8x²-(10-5x+x²) = 3[x-(2+x²)]

Answer 1

8x²-(10-5x+x²) = 3[x-(2+x²)]
8x²-10+5x-x² = 3[x-2-x²]
8x²-10+5x-x² = 3x-6-3x²
8x²+3x²+5x-x²-3x = -6+10
10x²+5x-3x = 4
10x²+2x = 4
10x²+2x-4 = 0

e resolvemos baskara..

Answer 2

8x²-(10-5x+x²) = 3[x-(2+x²)]
8x²-10+5x-x² = 3[x-2-x²]
8x²-10+5x-x² = 3x-6-3x²
8x²+3x²+5x-x²-3x = -6+10
10x²+5x-3x = 4
10x²+2x = 4
10x²+2x-4 = 0