Question

equação exponencial

8^3x=3√32^x÷4^x-1

Answer 1

Boa noite Pedrojoao

8^(3x) = ³√32^x/4^(x - 1)

8^(3x) = 32^(x/3)/4^(x - 1) 

8^(3x) = 2^(5x/3)/2^(2x - 2)

8^(3x) = 2^(5x/3 - 2x + 2)

8^(3x) = 2^(2 - x/3)

2^(9x) = 2^(2 - x/3)

9x = 2 - x/3

27x = 6 - x

28x = 6

x = 6/28 

x = 3/14