Question

Me ajudem!!! LOG1/2 4096

Answer 1

Lembrete:

⇒ $\log _{\frac{1}{b}}\left(a\right)=-\log _b\left(a\right)$
⇒ $\log _b\left(a^c\right)=c\cdot \log _b\left(a\right)$
⇒ $\log _a\left(a\right)=1$

$\log _{\frac{1}{2}}\left(4096\right)\\-\log _2\left(4096\right)\\-\log _2\left(2^{12}\right)\\-12\cdot \log _2\left(2\right)\\-12\cdot 1\\\boxed{\bold{-12}}$