Question

(x+1)ao quadrado -(2x+3)ao quadrado=0

Answer 1

(x+1)² - (2x+3)² = 0
x² + 2x + 1 - 4x² - 12x - 9 = 0
-3x² - 14x - 8 = 0

Δ = b² - 4ac
Δ = (-14)² - 4.(-3)(-8)
Δ = 196 - 96
Δ = 100

x = -b +- √Δ/2a (Bhaskara)
x = -(-14) +- √100/2.(-3)

x1 = 14+10/-6 = 24/-6 = -4
x2 = 14-10/-6 = 4/-6 = -2/3

S = {-2/3,-4}