Question

Obtenha o 11° termo da PG (1/27, 1/9 , 1/3, ...)

Answer 1

a11=1/27*3^10
a11=3^10/3^3
a11=3^7
a11=2187

Answer 2

Dados :

$\boxed{a_1= \frac{1}{27} }$

$\boxed{q= \frac{a_2}{a_1} ~\to~ \frac{ \frac{1}{9}}{ \frac{1}{27} } ~\to~3}$

$\boxed{a_{11}=~~?}$

Usando o termo Geral

$a_n=a_1*q^{n-1}\\ \\a_{11}=3^{-3}*3^{11-1}\\ \\a_{11}=3^{-3}*3^{10}\\ \\\boxed{a_{11}=3^{7}}$

ou 

$\boxed{a_{11}=2187}$