Question

(VALENDO 40 PONTOS)
Resolva o A) limite 3X² - x - 10 / x² - 4
x tende a 2
anexo abaixo da letra a) e b)

Answer 1

A)

$\lim_{x \to2} \dfrac{3x^2 - x- 10}{x^2 - 4} = \dfrac{(x-2)*(3x+5)}{(x+2)*(x-2)} \\ \\ \\ \lim_{x \to2} \dfrac{3x^2 - x- 10}{x^2 - 4} = \dfrac{3x+5}{x+2} = \dfrac{3*2+5}{2+2} = \dfrac{6+5}{4} = \dfrac{11}{4}$

B)

$\lim_{x \to2} \dfrac{x^2 + x- 6}{x^2 - x-2} = \dfrac{(x-2)*(x+3)}{(x-2)*(x+1)} \\ \\ \\ \lim_{x \to2} \dfrac{x^2 + x- 6}{x^2 - x-2} = \dfrac{x+3}{x+1} = \dfrac{2+3}{2+1} = \dfrac{5}{3}$