Question

Sendo log x a=2, log x b=3 e log x c=6 então , determine log x a²b³/raiz cubica de c


15

11


10


18


8

Answer 1

Boa noite Rogerio

logx(a) = 2
logx(b) = 3
logx(c) = 6

logx(a²b³/³√c) = 2logx(a) + 3log3(b) - logx(c)/3 
logx(a²b³/³√c) = 2*2 + 3*3 - 6/3 = 4 + 9 - 2  = 11