Question

se f(x)=2x elevado a 2 -1,então f(0)+f(-1)+f(1/2) e igual a:

Answer 1

$f(x)=2x^2-1\\ \\ f(0)+f(-1)+f(\frac{1}{2})=2.0^2-1+2(-1)^2-1+2.(\frac{1}{2})^2-1=\\ \\ \boxed{f(0)+f(-1)+f(\frac{1}{2})=0-1+2-1+\frac{1}{2}-1=-\frac{1}{2}}$