Question

Determine o valor de x no triângulo a seguir:
(Preciso da conta )

Answer 1

$\frac{x}{sen60^o} = \frac{120}{sen45^o} \\ \\ \frac{x}{ \frac{ \sqrt{3} }{2} } = \frac{120}{ \frac{ \sqrt{2} }{2} } \\ \\ \frac{2x}{ \sqrt{3} } = \frac{2.120}{ \sqrt{2} } \\ \\ x \sqrt{2} =120 \sqrt{3} \\ \\ 2x^2=14400.3 \\ \\ x^2=7200.3 \\ \\ x^2=3600. 6 \\ \\ x=60 \sqrt{6} cm$