Question

calcule quantos lados tem o poligono cuja soma das medidas dos angulos internos e: a)1.620° b)1.440°

Answer 1

a)1620 = S i
S i = 180(n - 2)
180(n - 2) = 1620
180 n - 360 = 1620
180 n = 1620 + 360
180 n = 1980
n = 1980 / 180
n = 11

b)S i = 1440
S i = 180(n - 2 )
180(n - 2 ) = 1440
180 n - 360 = 1440
180 n = 1440 + 360
180 n = 1800
n = 1800 / 180
n = 10

Answer 2

Resposta:a)1620 = S i

S i = 180(n - 2)

180(n - 2) = 1620

180 n - 360 = 1620

180 n = 1620 + 360

180 n = 1980

n = 1980 / 180

n = 11

b)S i = 1440

S i = 180(n - 2 )

180(n - 2 ) = 1440

180 n - 360 = 1440

180 n = 1440 + 360

180 n = 1800

n = 1800 / 180

n = 10