sejam as funções f(x) = x² + 1 e g(x) = 2x - 1, de R em R. Calcule (g o f)(2), (f o g)(-2) e (g o g)(1)
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f(x) = x²+1 e g(x) = 2x-1
g(x) =2x-1
gf(x)=2(x²+1)-1
gf(2) = 2(2²+1)-1
gf(2) = 2(4+1)-1
gf(2) =2.5-1
gf(2) =10-1
gf(2) =9
f(x) = x²+1
fg(x) =(2x-1)²+1
fg(-2) = ((2.(-2)-1))²+1
fg(-2) = (-4-1)²+1
fg(-2) = (-5)²+1
fg(-2) =25+1
fg(-2)=26
g(x) = 2x-1
gg(x) =2(2x-1)-1
gg(1) = 2(2.1-1)-1
gg(1) =2(2-1)-1
gg(1) =2.1-1
gg(1)= 1
g(x) =2x-1
gf(x)=2(x²+1)-1
gf(2) = 2(2²+1)-1
gf(2) = 2(4+1)-1
gf(2) =2.5-1
gf(2) =10-1
gf(2) =9
f(x) = x²+1
fg(x) =(2x-1)²+1
fg(-2) = ((2.(-2)-1))²+1
fg(-2) = (-4-1)²+1
fg(-2) = (-5)²+1
fg(-2) =25+1
fg(-2)=26
g(x) = 2x-1
gg(x) =2(2x-1)-1
gg(1) = 2(2.1-1)-1
gg(1) =2(2-1)-1
gg(1) =2.1-1
gg(1)= 1
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