Question

resolva a equação: sec^2x/cossec(x)*cosx
sabendo que tg(x)=3/2

Answer 1

$x = \frac{Sec^2(x)}{Cossec(x).cos(x)} \\ \\ x = \frac{ \frac{1}{cos^2(x)} }{ \frac{1}{sen(x)} .cos(x)} \\ \\ x = \frac{ \frac{1}{cos^2(x)} }{ \frac{cos(x)}{sen(x)}} = \frac{1}{cos^2(x)} }.{ \frac{sen(x)}{cos(x)} = \frac{1}{cos^2(x)} }.{ \frac{3}{2} = \frac{3}{2cos^2(x)} }$