Question

Interpole 8 meio entre 12 e 102

Answer 1

a1 = 12
a10 = 102 
n = 10

an = a1 + (n-1) * r
102 = 12 + (10-1) * r
102 = 12 + 9r
9r = 90
r = 90/9
r = 10

P.A. ( 12, 22, 32, 42, 52, 62, 72, 82, 92, 102)