Question

Como calcular o valor de (n+3)!     (n-1)!
______ . _____
  (n-2)!     (n+2)!

Answer 1

$Resolu\c{c}\~ao \to \left\{\begin{array}{ccc} \frac{(n+3)!(n-1)!}{(n-2)!(n+2)!} = \frac{(n+3)(n+2)!(n-1)(n-2)!}{(n-2)!(n+2)!} \\\\ \frac{(n+3)(n-1)}{1} = n^2-n+3n-3\\\\ \boxed{(n+3)(n-1)^}\\\\ou\\\\\boxed{n^2+2n-3} \end{array}\right$

Espero ter ajudado. :))