Question

$( 2^{-1 } + 2^{-2})^{-2}$ como resolver

Answer 1

$(2^{-1}+2^{-2})^{-2}\\\\( \frac{1}{2} + \frac{1}{4} )^{-2}\\\\( \frac{2}{4} + \frac{1}{4} )^{-2}\\\\( \frac{3}{4} )^{-2}\\\\( \frac{4}{3} )^{2}\\\\ \frac{4^{2}}{3^{2}} =\boxed{\boxed{ \frac{16}{9} }}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ok$