Question

Faça as seguintes conversoes
A) -114,1 °C p/K
B)78,5°C p/K
C)40°C p/F

Answer 1

Resolução da questão, veja:

Letra “A”:

Converter -114,1 °C para K:

$\mathsf{\Theta{K} = \Theta{\°C}+273,15}}~\to~\mathsf{-114,1~\°C}}}\\\\\\\\\ \mathsf{\Theta{K} = -114,1+273,15}}\\\\\\\\\\\ \large\boxed{\boxed{\boxed{\boxed{\boxed{\mathsf{\Theta{K} = 159,05.}}}}}}}}}}}}}}}}}}}}}$

Ou seja, -114,1 °C equivale a 159,05 K.

Letra “B”:

Converter 78,5 °C para K:

$\mathsf{\Theta{K} = \Theta{\°C}+273,15}}~\to~\mathsf{78,5~\°C}}}\\\\\\\\\ \mathsf{\Theta{K} = 78,5+273,15}}\\\\\\\\\\\ \large\boxed{\boxed{\boxed{\boxed{\boxed{\mathsf{\Theta{K} = 351,65.}}}}}}}}}}}}}}}}}}}}}$

Ou seja, 78,5 °C equivale a 351,65 K.

Letra “C”

Converter 40 °C para °F:

$\mathsf{\dfrac{\°C}{5}} = \mathsf{\dfrac{\°F-32}{9}}}~\to~\mathsf{40~\°C}}}\\\\\\\\\ \mathsf{\dfrac{40}{5}} = \mathsf{\dfrac{\°F-32}{9}}}\\\\\\\\\\ \mathsf{5\°F-160=360}}\\\\\\\\\ \mathsf{5\°F=360+160}}\\\\\\\\\\ \mathsf{5\°F = 520}}\\\\\\\\\\ \mathsf{\°F = \dfrac{520}{5}}}\\\\\\\\\ \large\boxed{\boxed{\boxed{\boxed{\boxed{\mathsf{\°F=104.}}}}}}}}}}}}}}}}}}}}}}}}}$

Ou seja, 40 °C equivale a 104 °F.

Espero que te ajude '-'