Question

gente me ajudeem por favor

Answer 1

a)
$3x-x^2 \geq 0\\x(-x+3) \geq 0\\x \geq 0\\-x+3 \geq 0\\x \leq 3$

b)
$\frac{x^2-5x+6}{3-x}\\\\x^2-5x+6 \geq 0\\(x-3).(x-2) \geq 0\\-x+3>0\\x<3\\ Logo: x >3$
c)

$\frac{6+x}{ \sqrt{1-x^2} }\\\\6+x \geq 0\\x \geq -6\\1-x^2>0\\-x^2>-1\\x^2<1\\x''<1\\x'<-1$

S= {xeR/$-6 \leq x<-1$ ou $x>1$ }