Question

limite de x^3-27/x^2-5x+6 x tendendo 2

Answer 1

Derivamos as funções:

Derivada: x³ - 27 = 3x²
Derivada: x² - 5x + 6 = 2x - 5

$\lim_{x \to 2} \dfrac{3x^2}{2x-5} = \dfrac{3.2^2}{2.2 - 5} = \dfrac{12}{-1} = -12$

Logo:

$\lim_{x \to 2} \dfrac{x^3-27}{x^2-5x+6} = -12$