Question

resolva a Equação log[3-2.log(1+x)]=0

Answer 1

log[3-2.log(1+x)]=0
log[3-2.log(1+x)]=0
10^0=3-2.log(1+x)
1=3-2.log(1+x)
1-3=-2.log(1+x)
-2=-2.log(1+x)
-2/-2=log(1+x)
log(1+x)=1
10¹=1+x
x=10-1
x=9