Question

Qual o valor da expressão:

$1^{4} + ( -2) ^{4} - ( -2) ^{3} + 3^{0} + 8 . 2^{-3} + 1^{5}$

Answer 1

$1^4+(-2)^4-(-2)^3+3^0+8.2^{-3}+1^5=\\ \\ 1+16+8+1+1+1=28$

Answer 2

$X=1^4+(-2)^4-(-2)^3+3^0+8\cdot2^{-3}+1^5$

Veja que:

$1^4=1$, $(-2)^4=16$, $(-2)^3=-8$

$3^0=1$, $8\cdot2^{-3}=8\cdot\dfrac{1}{8}=1$ e $1^5=1$.

Assim:

$X=1+16-(-8)+1+1+1=1+16+8+1+1+1$

$X=28$, ou seja,

$1^4+(-2)^4-(-2)^3+3^0+8\cdot2^{-3}+1^5=28$