Question

calcule as equaçoes abaixo

Answer 1

A=1 B=1 C=-6
$X=\frac{-B+- \sqrt{ b^{2}-4.a.c }}{2.a}$
$x= \frac{-1+- \sqrt{ 1^{1}-4.1.(-6) } }{2.1}$
$x= \frac{-1+- \sqrt{1+24} }{2}$
$x= \frac{-1+- \sqrt{23} }{2}$
$x= \frac{-1+-23}{2}$
$x= \frac{-1+2}{2} = \frac{1}{2}$
$x= \frac{-1-2}{2} = \frac{-3}{2}$