Question

como resolver x² - 28x + 192 = 0

Answer 1

$\frac{-(-28)+- \sqrt{(28)^2-4*1*192} }{2*1} = \frac{28+- \sqrt{16} }{2} = \frac{28+-4}{2}$

x1=(28+4)/2= 16
x2=(28-4)/2=12

Answer 2

∆=-28²-4.1.192
∆=784-768
∆=16

x=28±√16/2.1
x=28±4/2

x1=28+4/2
x1= 16

x2=28-4/2
x2=12