Ajuda eu?
Determine as raízes das equações a seguir:
a) x² -5x +6 = 0
b) 2y² + 3y -14 = 0
c) (2x+ 3) (x-1) = 3
Respostas
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x=-b+-√b²-4ac/2a b)x=-b+-√b²-4ac/2a c)2x²-2x+3x-3=0
x=5+-√(-5)²-4.1.6/2.1 x=-3+-√3²-4.2.(-14)/2.2 2x²+x-3=0
x=-3+-√9+112/4 x=-b+-√b²-4ac/2a
x=5+-√25-24/2 x=-3+-√121/4 x=-1+-√1²-4.2.(-3)/2.2
x=5+-√1/2 x=-3+-11/4 x=-1+-√1+24/4
x=5+-1/ x1=-3+11/4 x=-1+-√25/4
x1=5+1/2 x1=9/4 x=-1+-5/4
x1=6/2 x2=-3-11/4 x1=-1+5/4
x1=3 x1=4/4
x2=-14/4 x1=1
x2=5-1/2 x2=-7/2 x2=-1-5/4
x2=4/2 x2=-6/4
x2=2 x2=-3/2
x=5+-√(-5)²-4.1.6/2.1 x=-3+-√3²-4.2.(-14)/2.2 2x²+x-3=0
x=-3+-√9+112/4 x=-b+-√b²-4ac/2a
x=5+-√25-24/2 x=-3+-√121/4 x=-1+-√1²-4.2.(-3)/2.2
x=5+-√1/2 x=-3+-11/4 x=-1+-√1+24/4
x=5+-1/ x1=-3+11/4 x=-1+-√25/4
x1=5+1/2 x1=9/4 x=-1+-5/4
x1=6/2 x2=-3-11/4 x1=-1+5/4
x1=3 x1=4/4
x2=-14/4 x1=1
x2=5-1/2 x2=-7/2 x2=-1-5/4
x2=4/2 x2=-6/4
x2=2 x2=-3/2
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