Question

A analise de uma amostra de sabão revelou [H+]= 1.10-10M. Dtermine o pOH ?

Answer 1

[H+].[OH-] = $10^{-14}$
$10^{-10} . [OH-] = 10^{-14}$
[OH-] = $\frac{ 10^{-14} }{ 10^{-10} }$
[OH-] = $10^{-4}$

pOH = - log[OH-]
pOH = - log $10^{-4}$
pOH = - (-4) log 10
pOH = 4.1
pOH = 4