Question

Interpole três meios geométricos entre 2 e 1250

Answer 1

P,G.(2,-,-,-,1250
N = 5
An = a 5 = 1250
a n = a 1 .q^n - 1
1250 = 2 . q^5 - 1
1250/2 = q^4
625  = q^4
5^4 = q^4
q = 5
a 1 = 2
a 2 = 2. 5 = 10
a 3 = 10.5 = 50
a 4 = 50 . 5 = 250
a 5 = 250 . 5 = 1250
P.G.(2,10,50,250,1250)