Question

coloque na forma ax²+bx+c=0 equação do segundo grau

f x(x-2)+1=2(x+3)

g (x+3)²=1

h (x-5)²-9=0

i (x+1)²=x=7

j (x+4)²=3(x+2)

Answer 1

f)x(x-2)+1=2(x+3)
x²-2x+1= 2x+6
x²-2x-2x+1-6=0
x²-4x-5=0

g)(x+3)²= 1
(x+3).(x+3)= 1
x²+3x+3x+9= 1
x²+6x+9-1= 0
x²+6x+8= 0

h)(x-5)²-9= 0
(x-5).(x-5)-9= 0
x²-5x-5x+25-9= 0
x²-10x+16= 0

i)(x+1)²=x-7
(x+1).(x+1)= x-7
x²+x+x+1= x-7
x²+x+x+1-x+7= 0
x²+x+8= 0

j)(x+4)²= 3(x+2)
(x+4).(x+4)= 3x+6
x²+4x+4x+16= 3x+6
x²+4x+4x+16-3x-6= 0
x²+5x+10= 0