Question

a) 0,5x+1,4x+2,8x-2x
                                                                                         
b)x²y³-2x²y³+x²y³
    4      3

Answer 1

Resolução:

a) 
$0,5x+1,4x+2,8x-2x\text{ (Colocando o x em evidencia)}\\x\cdot \left(0,5+1,4+2,8-2\right)\\x\cdot \left(1,9+2,8-2\right)\\x\cdot \left(1,9+0,8\right)\\x\cdot 2,7\\\boxed{\bold{2,7x}}$

b)
$\dfrac{x^2y^3}{4}-\dfrac{2x^2y^3}{3}+x^2y^3\text{ (O MMC de 3 e 4 e 12)}\\\\\dfrac{3\cdot x^2y^3}{3\cdot 4}-\dfrac{4\cdot 2x^2y^3}{4\cdot 3}+\dfrac{12x^2y^3}{12}\\\\\dfrac{3x^2y^3}{12}-\dfrac{8x^2y^3}{12}+\dfrac{12x^2y^3}{12}\\\\\dfrac{3x^2y^3-8x^2y^3+12x^2y^3}{12}\\\\\dfrac{x^2y^3\cdot \left(3-8+12\right)}{12}\\\\\dfrac{x^2y^3\cdot \left(-5+12\right)}{12}\\\\\dfrac{x^2y^3\cdot 7}{12}\\\\\boxed{\bold{\frac{7x^2y^3}{12}}}$