• Matéria: Matemática
  • Autor: beatrizsouzalin
  • Perguntado 8 anos atrás

-1/4x4-3x³+1-x²+3x4-8+1/2x²+5x³-4x

Respostas

respondido por: valsantina
2
-1/4x⁴+3x⁴-3x³+5x³-x²+1/2x²-4x-8+1=

11/4x⁴ +2x³ -1/2x² -4x -7
respondido por: Anônimo
1

Resposta:

-\frac{1}{4}x^4-3x^3+1-x^2+3x^4-8+\frac{1}{2}x^2+5x^3-4x^1\\\\Resposta: =\frac{11x^4}{4}+2x^3-\frac{x^2}{2}-4x-7

-\frac{1}{4}x^4-3x^3+1-x^2+3x^4-8+\frac{1}{2}x^2+5x^3-4x^1\\\\-\frac{1}{4}x^4-3x^3+1-x^2+3x^4-8+\frac{1}{2}x^2+5x^3-4x\\\\-\frac{1}{4}x^4+3x^4-3x^3+5x^3+\frac{1}{2}x^2-x^2-4x+1-8\\\\-\frac{1}{4}x^4+3x^4-3x^3+5x^3-\frac{1}{2}x^2-4x+1-8\\\\-\frac{1}{4}x^4+3x^4+2x^3-\frac{1}{2}x^2-4x+1-8\\\\\frac{11}{4}x^4+2x^3-\frac{1}{2}x^2-4x+1-8\\\\\frac{11x^4}{4}+2x^3-\frac{x^2}{2}-4x+1-8\\\\\frac{11x^4}{4}+2x^3-\frac{x^2}{2}-4x-7

Perguntas similares