Question

(x-2)² +4 (x-1) (x+2)=16 resolva , em R a equação

Answer 1

(x-2)^2+4(x-1)(x+2)=16
(x)^2-2(x)(2)+(2)^2+(4x-4)(x+2)=16
x^2-4x+4+4x^2+8x-4x-8=16
5x^2-8x+8x-4=16
5x^2-4-16=0
5x^2-20=0
5x^2=20
x^2=20/5
x^2=4
x=+,-\/4
x=+,-2