Question

x²+12x+11=0 Me ajudemm! Plis

Answer 1

Resolva por bhaskara e delta
Delta = b^2 - 4ac
Delta = 144 - 4*1 *11
Delta = 100
X = - B +-raiz de delta /2a
X1 = - 12 + 10 / 2 = - 1
X2= - 12 - 10 /2 = - 11

Answer 2

Olá, boa noite ☺

Resolução:

x² + 12x + 11=0

a=1
b=12
c=11

$\Delta= b^2 -4.a.c \\ \Delta= 12^2-4.1.11 \\ \Delta=144 - 44 \\ \Delta=100$

Valores de x:

$x= \frac{-b\pm \sqrt{\Delta} }{2.a} \\ \\ x= \frac{-12\pm \sqrt{100}}{2.1} \\ \\ x= \frac{-12 \pm 10}{2} \\ \\ x'= \frac{-12+10}{2}= \frac{-2}{2}=-1 \\ \\ x''= \frac{-12-10}{2}= \frac{-22}{2}=-11$

Bons estudos :)