Question

Fala, brow! Me ajuda a resolver uma função logarítmica aqui? Jaé:

log base2 (3 + k) / (2 + k) = 1

Answer 1

$\mathrm{\log_2{\bigg(\dfrac{3+k}{2+k}\bigg)}=1\ \to\ \log_2{\bigg(\dfrac{3+k}{2+k}\bigg)}=\log_2{2}}\\\\\\ \mathrm{\dfrac{3+k}{2+k}=2\ \to\ 3+k=2.(2+k)}\\\\\\ \mathrm{3+k=4+2k\ \to\ 3-4=2k-k}\\\\\\ \mathbf{k=-1}$