Question

Poe favor alguem me ajuda com essa expresao dos complexos (1-i)(i-2i)(3-3i)+1+2i+3i

Answer 1

(1-i)(i-2i)(3-3i)+1+2i+3i=
1i-2i-i^2+2i^2+3-3i-3i-3i^2+1+2i+3i=
1i-2i-i(-1)+2(-1)+3-3i-3i+3(-1)+1+2i+3i=
1i-2i+1-2+3-3i-3i-3+1+2i+3i=
1-2+3-3+1+1i-2i-3i-3i+2i+3i=
0-2i
Acredito que seja essa a resposta