Question

x²-4x-5=0
x²-5x+8=0
me ajudeeem

Answer 1

x²-4x-5=0

(A= 1, B= -4 e C=-5)

(regra de baskara)

x=4±√4²-4·1·(-5)/2·1

x=4±√16+20/2

x=4±√36/2

x=4±6/2



x'= 4+6/2

x'=10/2

x'= 5



x"=4-6/2

x"= -2/2

x"=-1







x²-5x+8=0

(A=1 ,B=-5 e C= 8)

(regra de baskara)



x= 5±√5²-4·1·8/2·1

x=5±√25-32/2·1

x=5±√-7/2



x'= 5+√-7/2



x"= 5-√-7/2