Question

as diagonais de um losano medem 96 cm e 72 cm. calcule a medida do lado do losango

Answer 1

Por Pitágoras:

$L^2 = ( \dfrac{D}{2})^2 + (\dfrac{d}{2} )^2 \\ \\ \\ L^2 = ( \dfrac{96}{2})^2 + (\dfrac{72}{2} )^2 \\ \\ \\ L^2 = 48^2 + 36^2 \\ \\ \\ L^2 = 2304 + 1296 \\ \\ \\ L^2 = 3600 \\ \\ \\ L = \sqrt{3600} \\ \\ \\ L = 60~ cm$