Question

$3 x^{2} -10x-8-0$

Answer 1

$3x^2-10x-8=0 \\ \Delta=(-10)^2-4.3.(-8)=100+96=196 \\ x=\frac{10+-\sqrt{196}}{2.3}=\frac{10+-14}{6} \\ x_1=\frac{2}{3} \\ x_2=4$